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:hug: for DJ

Cause I do not have enough coaxial cable to move the modem to my brother's room but chances are he isn't gonna wanna move his computer back downstairs either...So, I will need to run the cable from the modem in my room to his computer in his.

I already got one. I need to get a straight thru cable of the same length for September prolly. Like you said though, shipping woudl prolly make it not even worth it...

Yes! That is what I need! I paid almost $30 for a 40 or 45' cross over cable

No, no, no, I just wanna have some incase I ever need them. I realize what you have is in 33m pieces. When I networked our computers at my house I have to pay a pretty penny for a networking cable.

So, I guess I have to be looking for patch cords since I don't have a crimping tool...

I think CAT5 is what I want but I don't have a crimping tool :(

OH! Before that last post even matters...does this stuff already have the ends on it?

*scratches head* It would prolly be cheaper for me to go buy it then pay shipping on like 90meters of Cat5 woudln't it?

How many meters is 100'?

haha Civic! Reminds me of Woodbridge! I will not state an opinion on the dropping of said truck as I have some extremem feelings against such things. They look UBER cool but all functionaity is gone...

OH! I could do with some Cat5!

:)

You are gonna get me in trouble Mr Professur. I keep laughing out loud when I read yoru posts.

ROFL! That is the quote of the day!!!

WELCOME BACK!

Glad I could be of assistance Les :)

If you need anything else I will be back and forth here all day and also might have ICQ on. i am going to PM you my work email though because excluding my hour lunch you should beable to reach me at that right up until 5pm :)

m = 1/3rb^2 You can use cross mutilplication here. The general rule is: If a/b = c/d, then ad = bc So, m(3rb^2) = 1 Since it's multiplication you can move the brackets whereever you want since they don't reall yhave a purpose except to visually seperate. So, (m3r)b^2 = 1 Divide...

4x/5 = 11 + x/4 First step is to get a common denominator. The LCD for 5, 1 and 4 woudl be 20. So, 16x/20 = 220/20 + 5x/20 This is the same as: 16x = 220 + 5x From here you rearrange and solve: 16x - 5x = 220 +5x - 5x 11x = 220 x = 20